Fortran To Assembly Converter

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Convert hundreds of lines of Fortran code into Assembly with one click. Completely free, no sign up required.

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What Is Fortran To Assembly Converter?

A Fortran To Assembly converter is an online tool designed to transform code written in Fortran into Assembly language. Utilizing technologies such as generative AI, machine learning, and natural language processing, this tool efficiently bridges the gap between high-level programming and low-level machine instructions. It simplifies the coding process, making it more accessible for developers who aim to optimize their applications or port existing codebases.

The conversion process operates in three distinct steps:

  1. Input: You enter the Fortran code that needs conversion. This is the initial stage where users paste or upload their existing Fortran code into the tool.
  2. Processing: The tool analyzes and processes the code using advanced algorithms. It carefully interprets the high-level constructs of Fortran, mapping them to equivalent Assembly language instructions while maintaining the original logic and structure.
  3. Output: The converted Assembly code is generated and presented for use. At this stage, users receive a formatted output that can be directly integrated into their projects or further refined as needed.

How Is Fortran Different From Assembly?

Fortran and Assembly represent two ends of the programming spectrum, each tailored for specific tasks in the realm of computing. Fortran, characterized as a high-level programming language, is designed for numerical and scientific computing. It allows programmers to concentrate on solving complex mathematical problems without getting bogged down by the intricacies of hardware. In contrast, Assembly language operates at a low level, offering direct access to hardware controls and CPU instructions. Understanding these core differences is essential if you’re considering converting Fortran code into Assembly, as each language serves unique purposes that cater to different computing needs.

  • Abstraction: Fortran’s high-level abstractions allow developers to focus on solving problems by using well-defined functions and structures. This abstraction simplifies code development, letting engineers concentrate on algorithms rather than hardware details. On the other hand, Assembly requires meticulous attention to the hardware’s architecture, as the programmer must manage memory and processor instructions directly.
  • Portability: One of Fortran’s strengths is its portability; code written in Fortran often runs seamlessly on diverse platforms with minimal changes. Conversely, Assembly is closely tied to specific hardware architectures, meaning code may require extensive rewriting to function on different systems.
  • Syntax: Fortran’s syntax is designed for readability, integrating built-in functions that make understanding the code straightforward. In contrast, Assembly language relies on mnemonics that correlate directly to machine-readable instructions, which can be less intuitive for many developers.
  • Execution Speed: Fortran is optimized for mathematical computations, making it efficient for such tasks. However, Assembly allows programmers to fine-tune performance at a very granular level, enabling potentially faster execution times for critical operations that require optimization.
Feature Fortran Assembly
Level of Abstraction High-Level Low-Level
Portability High Low
Readability More Readable Less Readable
Performance Optimized for Math Highly Optimizable
Typability Strong Typing Weak Typing

How Does Minary’s Fortran To Assembly Converter Work?

Begin by detailing your task in the designated text box on the left side of the Minary’s Fortran To Assembly converter. Describe what you need, whether it’s translating a specific Fortran program or understanding its assembly counterpart. Once you’ve filled in the details, hit the “Generate” button. The generator then processes your request, translating your Fortran code into assembly language, which appears on the right side of the interface.

What you see is a clear, structured assembly code that reflects your input. If you find the output satisfactory, you can easily copy the generated code using the copy button located at the bottom. This seamless experience not only aids in your coding tasks but also simplifies learning about assembly principles.

In line with improving user experience, Minary encourages feedback on the generated output. You’ll notice feedback vote buttons right next to the output area. If the code meets your expectations, give it a thumbs up; otherwise, let them know it didn’t hit the mark. This feedback loop is designed to train and refine the AI’s capabilities continuously, ensuring a more tailored service for your future requests.

For example, if you input a prompt such as “Convert this Fortran code to assembly: subroutine example(a, b) result(c)”, you can see the resulting assembly code reflect your original Fortran intentions. The more detailed your descriptions, the more accurate the translations from the Fortran To Assembly converter will be.

Examples Of Converted Code From Fortran To Assembly

program factorial_calculator
implicit none
integer :: n, result

! Prompt the user for input
print *, “Enter a non-negative integer:”
read *, n

! Check for non-negativity
if (n < 0) then print *, "Error: Factorial is not defined for negative integers." else result = factorial(n) print *, "The factorial of", n, "is", result end if contains function factorial(num) result(fact) integer, intent(in) :: num integer :: fact integer :: i fact = 1 do i = 2, num fact = fact * i end do end function factorial end program factorial_calculator

section .data
prompt db “Enter a non-negative integer:”, 0
error_msg db “Error: Factorial is not defined for negative integers.”, 0
result_msg db “The factorial of “, 0
is_msg db ” is “, 0

section .bss
n resb 4
result resb 4
temp resb 4

section .text
global _start

_start:
; Prompt the user for input
mov rax, 1 ; syscall: write
mov rdi, 1 ; file descriptor: stdout
mov rsi, prompt ; message to write
mov rdx, 30 ; message length
syscall

; Read user input
mov rax, 0 ; syscall: read
mov rdi, 0 ; file descriptor: stdin
mov rsi, n ; buffer to read into
mov rdx, 4 ; number of bytes to read
syscall

; Convert the input from string to integer
; Assuming input is properly formatted, you will need proper conversion logic here.

; Check if n is negative
mov eax, [n]
cmp eax, 0
jl .negative_case

; Calculate factorial
mov eax, 1 ; fact = 1
mov ecx, 2 ; i = 2

.factorial_loop:
cmp ecx, [n] ; compare i with num
jg .end_factorial ; if i > num, exit loop
imul eax, ecx ; fact = fact * i
inc ecx ; i++
jmp .factorial_loop

.end_factorial:
; Print result
; Print “The factorial of ”
mov rax, 1 ; syscall: write
mov rdi, 1 ; file descriptor: stdout
mov rsi, result_msg ; message to write
mov rdx, 27 ; message length
syscall

; Print n
; Assume you have a function to convert integer to string and print it

; Print ” is ”
mov rax, 1 ; syscall: write
mov rdi, 1 ; file descriptor: stdout
mov rsi, is_msg ; message to write
mov rdx, 4 ; message length
syscall

; Print result
; Assume you have a function to convert integer to string and print it

jmp .exit

.negative_case:
; Print error message
mov rax, 1 ; syscall: write
mov rdi, 1 ; file descriptor: stdout
mov rsi, error_msg ; message to write
mov rdx, 43 ; message length
syscall

.exit:
mov rax, 60 ; syscall: exit
xor rdi, rdi ; exit code 0
syscall

program BankAccountManagement
implicit none
integer :: choice, accountNumber
type :: Transaction
character(len=20) :: type
real :: amount
end type Transaction

type :: BankAccount
integer :: accountNumber
real :: balance
integer :: transactionCount
type(Transaction), allocatable :: transactions(:)
end type BankAccount

integer, parameter :: maxAccounts = 100
type(BankAccount), allocatable :: accounts(:)
integer :: accountCount

accountCount = 0
allocate(accounts(maxAccounts))

do
print *, “Welcome to the Bank Account Management System”
print *, “1. Create Account”
print *, “2. Check Balance”
print *, “3. Deposit Money”
print *, “4. Withdraw Money”
print *, “5. Exit”
print *, “Enter your choice: ”
read(*, *) choice

select case (choice)
case (1)
call createAccount()
case (2)
call checkBalance()
case (3)
call depositMoney()
case (4)
call withdrawMoney()
case (5)
exit
case default
print *, “Invalid choice, please try again.”
end select
end do

contains

subroutine createAccount()
integer :: accountNumber
accountCount = accountCount + 1
if (accountCount > maxAccounts) then
print *, “Maximum accounts reached.”
accountCount = accountCount – 1
return
end if
accountNumber = accountCount
accounts(accountCount)%accountNumber = accountNumber
accounts(accountCount)%balance = 0.0
accounts(accountCount)%transactionCount = 0
allocate(accounts(accountCount)%transactions(0))
print *, “Account created successfully! Your account number is: “, accountNumber
end subroutine createAccount

subroutine checkBalance()
integer :: accNum
print *, “Enter your account number: ”
read(*, *) accNum
if (accNum < 1 .or. accNum > accountCount) then
print *, “Invalid account number.”
else
print *, “Your balance is: “, accounts(accNum)%balance
end if
end subroutine checkBalance

subroutine depositMoney()
integer :: accNum
real :: amount
print *, “Enter your account number: ”
read(*, *) accNum
if (accNum < 1 .or. accNum > accountCount) then
print *, “Invalid account number.”
return
end if
print *, “Enter amount to deposit: ”
read(*, *) amount
if (amount <= 0.0) then print *, "Deposit amount must be positive." return end if accounts(accNum)%balance = accounts(accNum)%balance + amount accounts(accNum)%transactionCount = accounts(accNum)%transactionCount + 1 allocate(accounts(accNum)%transactions(accounts(accNum)%transactionCount - 1)) accounts(accNum)%transactions(accounts(accNum)%transactionCount)%type = "Deposit" accounts(accNum)%transactions(accounts(accNum)%transactionCount)%amount = amount print *, "Deposited successfully." end subroutine depositMoney subroutine withdrawMoney() integer :: accNum real :: amount print *, "Enter your account number: " read(*, *) accNum if (accNum < 1 .or. accNum > accountCount) then
print *, “Invalid account number.”
return
end if
print *, “Enter amount to withdraw: ”
read(*, *) amount
if (amount <= 0.0) then print *, "Withdrawal amount must be positive." return end if if (amount > accounts(accNum)%balance) then
print *, “Insufficient funds.”
return
end if
accounts(accNum)%balance = accounts(accNum)%balance – amount
accounts(accNum)%transactionCount = accounts(accNum)%transactionCount + 1
allocate(accounts(accNum)%transactions(accounts(accNum)%transactionCount – 1))
accounts(accNum)%transactions(accounts(accNum)%transactionCount)%type = “Withdrawal”
accounts(accNum)%transactions(accounts(accNum)%transactionCount)%amount = amount
print *, “Withdrawn successfully.”
end subroutine withdrawMoney

end program BankAccountManagement

program BankAccountManagement
implicit none
integer :: choice, accountNumber
type :: Transaction
character(len=20) :: type
real :: amount
end type Transaction

type :: BankAccount
integer :: accountNumber
real :: balance
integer :: transactionCount
type(Transaction), allocatable :: transactions(:)
end type BankAccount

integer, parameter :: maxAccounts = 100
type(BankAccount), allocatable :: accounts(:)
integer :: accountCount

accountCount = 0
allocate(accounts(maxAccounts))

do
print *, “Welcome to the Bank Account Management System”
print *, “1. Create Account”
print *, “2. Check Balance”
print *, “3. Deposit Money”
print *, “4. Withdraw Money”
print *, “5. Exit”
print *, “Enter your choice: ”
read(*, *) choice

select case (choice)
case (1)
call createAccount()
case (2)
call checkBalance()
case (3)
call depositMoney()
case (4)
call withdrawMoney()
case (5)
exit
case default
print *, “Invalid choice, please try again.”
end select
end do

contains

subroutine createAccount()
integer :: accountNumber
accountCount = accountCount + 1
if (accountCount > maxAccounts) then
print *, “Maximum accounts reached.”
accountCount = accountCount – 1
return
end if
accountNumber = accountCount
accounts(accountCount)%accountNumber = accountNumber
accounts(accountCount)%balance = 0.0
accounts(accountCount)%transactionCount = 0
allocate(accounts(accountCount)%transactions(0))
print *, “Account created successfully! Your account number is: “, accountNumber
end subroutine createAccount

subroutine checkBalance()
integer :: accNum
print *, “Enter your account number: ”
read(*, *) accNum
if (accNum < 1 .or. accNum > accountCount) then
print *, “Invalid account number.”
else
print *, “Your balance is: “, accounts(accNum)%balance
end if
end subroutine checkBalance

subroutine depositMoney()
integer :: accNum
real :: amount
print *, “Enter your account number: ”
read(*, *) accNum
if (accNum < 1 .or. accNum > accountCount) then
print *, “Invalid account number.”
return
end if
print *, “Enter amount to deposit: ”
read(*, *) amount
if (amount <= 0.0) then print *, "Deposit amount must be positive." return end if accounts(accNum)%balance = accounts(accNum)%balance + amount accounts(accNum)%transactionCount = accounts(accNum)%transactionCount + 1 allocate(accounts(accNum)%transactions(accounts(accNum)%transactionCount - 1)) accounts(accNum)%transactions(accounts(accNum)%transactionCount)%type = "Deposit" accounts(accNum)%transactions(accounts(accNum)%transactionCount)%amount = amount print *, "Deposited successfully." end subroutine depositMoney subroutine withdrawMoney() integer :: accNum real :: amount print *, "Enter your account number: " read(*, *) accNum if (accNum < 1 .or. accNum > accountCount) then
print *, “Invalid account number.”
return
end if
print *, “Enter amount to withdraw: ”
read(*, *) amount
if (amount <= 0.0) then print *, "Withdrawal amount must be positive." return end if if (amount > accounts(accNum)%balance) then
print *, “Insufficient funds.”
return
end if
accounts(accNum)%balance = accounts(accNum)%balance – amount
accounts(accNum)%transactionCount = accounts(accNum)%transactionCount + 1
allocate(accounts(accNum)%transactions(accounts(accNum)%transactionCount – 1))
accounts(accNum)%transactions(accounts(accNum)%transactionCount)%type = “Withdrawal”
accounts(accNum)%transactions(accounts(accNum)%transactionCount)%amount = amount
print *, “Withdrawn successfully.”
end subroutine withdrawMoney

end program BankAccountManagement

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