Fortran To Objective-C Converter

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Convert hundreds of lines of Fortran code into Objective-C with one click. Completely free, no sign up required.

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What Is Fortran To Objective-C Converter?

A Fortran to Objective-C converter is an online tool that utilizes advanced technologies like generative AI, machine learning, and natural language processing to translate Fortran code into Objective-C. This utility meets the common needs of developers to modernize or maintain legacy applications without starting anew. By employing this converter, you can transfer your codebase while preserving its original functionality.

The conversion process generally consists of three steps:

  1. Input: You begin by supplying the Fortran code you wish to convert.
  2. Processing: The tool then analyzes the input code, applying AI algorithms and models to effectively translate the syntax and semantic structures into Objective-C.
  3. Output: Finally, you receive the corresponding Objective-C code, which is ready for immediate implementation.

How Is Fortran Different From Objective-C?

Fortran and Objective-C serve distinct purposes in the programming world, each excelling in its own domain. Fortran has long been recognized as a powerhouse in numerical and scientific computing, providing the tools needed to perform complex mathematical calculations efficiently. On the other hand, Objective-C is a key player in the development of applications for macOS and iOS, leveraging its object-oriented design to create rich, user-friendly interfaces. Transitioning from Fortran to Objective-C can seem daunting, but understanding their core differences will facilitate a smoother adaptation of your coding skills.

When comparing these two languages, several key features stand out:

  • Programming Paradigm: Fortran employs a procedural programming paradigm, concentrating on a linear approach where functions and procedures are the backbone of execution. This is ideal for those focused on straightforward computation. In contrast, Objective-C adopts an object-oriented paradigm, which promotes modularity. Here, the focus shifts from actions to objects, allowing for better organization of code and enabling developers to reuse components easily.
  • Memory Management: In Fortran, managing memory is a manual task, requiring programmers to explicitly allocate and deallocate resources. This could be a source of errors but gives greater control to the programmer. Conversely, Objective-C leverages Automatic Reference Counting (ARC), which automatically manages memory usage, thus streamlining the development process and reducing the risk of memory leaks.
  • Syntax: Fortran’s syntax is designed to be straightforward, catering well to its primary role in mathematical computations. Objective-C’s syntax is inherently more verbose, reflecting its object-oriented features and aiming to facilitate clearer communication of the program’s structure and behavior.
Feature Fortran Objective-C
Paradigm Procedural Object-oriented
Memory Management Manual Automatic (ARC)
Syntax Simpler More verbose
Application Domain Scientific Computing App Development
Standard Libraries Focused on numerical methods Extensive Cocoa framework

How Does Minary’s Fortran To Objective-C Converter Work?

The generator begins by presenting you with a detailed input field, asking you to clearly describe the task at hand. You have complete control over this process; simply enter the specifics of the Fortran code you want to convert to Objective-C in the designated box on the left. Once your details are ready, click the ‘Generate’ button right next to it, initiating the conversion process.

As soon as you click ‘Generate,’ the system processes your input and produces the equivalent Objective-C code, which appears on the right side of the interface. Here, you can easily review the generated code and, if it meets your expectations, click the ‘Copy’ button at the bottom to save the output for your use.

To enhance the generator’s learning curve, you’ll find feedback vote buttons accompanying the code. If the output aligns with your needs, give it a thumbs up; if not, provide a thumbs down. This feedback contributes to refining the algorithms of the Fortran to Objective-C converter, ensuring continuous improvement.

For instance, if your task is to convert a simple Fortran function that calculates the factorial of a number, describe it in detail: “Convert the Fortran factorial function to Objective-C, ensuring proper handling of input values.” Clicking ‘Generate’ then yields the corresponding Objective-C code snippet, ready for integration into your project.

Examples Of Converted Code From Fortran To Objective-C

program factorial_calculator
implicit none
integer :: number, result

! Prompt user for input
print *, “Enter a positive integer to calculate its factorial: ”
read *, number

! Check for non-negative input
if (number < 0) then print *, "Factorial is not defined for negative integers." stop end if ! Calculate factorial result = factorial(number) ! Print the result print *, "The factorial of ", number, " is ", result end program factorial_calculator recursive function factorial(n) result(fact) integer, intent(in) :: n integer :: fact if (n == 0) then fact = 1 else fact = n * factorial(n - 1) end if end function factorial

#import

@interface FactorialCalculator : NSObject

– (NSInteger)factorial:(NSInteger)n;
– (void)run;

@end

@implementation FactorialCalculator

– (NSInteger)factorial:(NSInteger)n {
if (n == 0) {
return 1;
} else {
return n * [self factorial:n – 1];
}
}

– (void)run {
NSInteger number;
NSLog(@”Enter a positive integer to calculate its factorial: “);
scanf(“%ld”, &number);

if (number < 0) { NSLog(@"Factorial is not defined for negative integers."); return; } NSInteger result = [self factorial:number]; NSLog(@"The factorial of %ld is %ld", number, result); } @end int main(int argc, const char * argv[]) { @autoreleasepool { FactorialCalculator *calculator = [[FactorialCalculator alloc] init]; [calculator run]; } return 0; }

program SimpleCalculator
implicit none
real :: num1, num2, result
character(10) :: operator
integer :: choice

print *, “Welcome to the Simple Calculator!”

do
print *, “Enter the first number (or type ‘exit’ to quit):”
read *, num1
if (num1 == ‘exit’) exit

print *, “Enter an operator (+, -, *, /):”
read *, operator

print *, “Enter the second number:”
read *, num2

select case (operator)
case (‘+’)
result = num1 + num2
print *, “Result: “, result
case (‘-‘)
result = num1 – num2
print *, “Result: “, result
case (‘*’)
result = num1 * num2
print *, “Result: “, result
case (‘/’)
if (num2 == 0.0) then
print *, “Error: Division by zero is not allowed.”
else
result = num1 / num2
print *, “Result: “, result
end if
case default
print *, “Error: Invalid operator.”
end select

print *, “Do you want to continue? (1 for Yes, 0 for No):”
read *, choice
if (choice == 0) exit

end do

print *, “Thank you for using the Simple Calculator!”
end program SimpleCalculator

#import

int main(int argc, const char * argv[]) {
@autoreleasepool {
float num1, num2, result;
char operator[2];
int choice;

NSLog(@”Welcome to the Simple Calculator!”);

while (1) {
NSLog(@”Enter the first number (or type ‘exit’ to quit):”);

char input[50];
scanf(“%s”, input);
if (strcmp(input, “exit”) == 0) {
break;
}
num1 = atof(input);

NSLog(@”Enter an operator (+, -, *, /):”);
scanf(“%s”, operator);

NSLog(@”Enter the second number:”);
scanf(“%f”, &num2);

if (operator[0] == ‘+’) {
result = num1 + num2;
NSLog(@”Result: %f”, result);
} else if (operator[0] == ‘-‘) {
result = num1 – num2;
NSLog(@”Result: %f”, result);
} else if (operator[0] == ‘*’) {
result = num1 * num2;
NSLog(@”Result: %f”, result);
} else if (operator[0] == ‘/’) {
if (num2 == 0.0) {
NSLog(@”Error: Division by zero is not allowed.”);
} else {
result = num1 / num2;
NSLog(@”Result: %f”, result);
}
} else {
NSLog(@”Error: Invalid operator.”);
}

NSLog(@”Do you want to continue? (1 for Yes, 0 for No):”);
scanf(“%d”, &choice);
if (choice == 0) {
break;
}
}

NSLog(@”Thank you for using the Simple Calculator!”);
}
return 0;
}

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