Fortran To COBOL Converter
Other Fortran Converters
What Is Fortran To COBOL Converter?
A Fortran to COBOL converter is an online tool designed to facilitate the transition of code between these two programming languages. By harnessing technologies such as generative AI, machine learning, and natural language processing, it effectively transforms Fortran code into COBOL. This process is crucial for organizations looking to modernize legacy systems without starting from scratch.
The converter operates through a three-step process:
- Input: You begin by providing the source code written in Fortran. This could be a single function or an entire program, ensuring that the converter has all the context it needs.
- Processing: The tool then analyzes the input code in detail, breaking it down into its fundamental components. It identifies the syntax and logic of the Fortran code and maps these elements to their COBOL equivalents, ensuring that functional integrity is maintained during the conversion.
- Output: Finally, you receive the translated COBOL code. This output is structured for immediate implementation or further development. You can review the translated code for any necessary adjustments.
How Is Fortran Different From COBOL?
Fortran and COBOL serve distinct purposes in the programming world. Fortran is tailored for scientific and numerical computing, making it ideal for tasks that involve complex mathematical calculations and extensive data processing. It is commonly used in fields such as physics, engineering, and computational research. In contrast, COBOL shines in the realm of business applications, where the focus is on handling data, generating reports, and following structured programming paradigms. If you are contemplating converting Fortran code to COBOL, grasping these key differences is essential for a smooth transition.
Fortran has several important features that set it apart:
- It excels in performing calculations with high precision, making it a go-to choice for numerical analysis.
- Fortran efficiently manages arrays, including multidimensional ones, which is crucial for handling complex datasets.
- The language supports a procedural programming approach, allowing for modular structures that help organize code logically.
On the flip side, COBOL offers a different set of strengths:
- Its syntax resembles English, which improves readability and makes it accessible to those who may not be deeply technical.
- COBOL is built for robust file handling and meticulous data management, areas vital for organizational operations.
- The language prioritizes business logic, clearly defining processes and reporting, which aids in effective decision-making.
| Feature | Fortran | COBOL |
|---|---|---|
| Primary Use | Focused on scientific and engineering applications | Designed for business and administrative applications |
| Syntax | Compact, often requiring familiarity to navigate | Verbose and structured for clear understanding |
| Data Types | Offers complex data types and array variations | Provides strong support for decimal and text types |
| Performance | Optimized for intensive numerical computations | Focused on processing data and managing records |
How Does Minary’s Fortran To COBOL Converter Work?
Start by describing your task in the designated field on the left. This is where you provide a detailed explanation of what you want to convert. The more specific you are, the better the results you’ll receive from the Fortran To COBOL converter. Once you’re satisfied with your description, simply click the generate button.
The generator processes your request and displays the translated code on the right side of the interface. You can easily copy the generated code with a click of the copy button located at the bottom, making it convenient for you to use in your projects.
For feedback, you’ll notice rating buttons. Use these to let us know if the generated code meets your expectations. Your feedback is valuable and will help improve the Fortran To COBOL converter’s performance by automatically training the underlying model.
To illustrate how effective this process can be, consider a prompt like: “Convert the following Fortran code that calculates the factorial of a number into COBOL.” After typing this, hit generate, and within moments, you’ll see the equivalent COBOL code ready for use.
Engaging with the Minary’s Fortran To COBOL converter is straightforward and designed to cater to your specific coding needs while ensuring a smooth experience.
Examples Of Converted Code From Fortran To COBOL
implicit none
integer :: n, result
! Prompt the user for input
print *, ‘Enter a positive integer:’
read *, n
! Check if the input is a positive integer
if (n < 0) then
print *, 'Factorial is not defined for negative integers.'
stop
end if
! Calculate the factorial
result = factorial(n)
! Print the result
print *, 'The factorial of', n, 'is', result
contains
! Recursive function to calculate factorial
integer function factorial(num)
integer :: num
if (num == 0) then
factorial = 1
else
factorial = num * factorial(num - 1)
end if
end function factorial
end program factorial_calculator
PROGRAM-ID. factorial-calculator.
ENVIRONMENT DIVISION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 n PIC 9(3).
01 result PIC 9(20).
01 ws-negative PIC X(30) VALUE ‘Factorial is not defined for negative integers.’.
01 ws-prompt PIC X(30) VALUE ‘Enter a positive integer:’.
01 ws-output PIC X(50).
PROCEDURE DIVISION.
DISPLAY ws-prompt.
ACCEPT n.
IF n < 0 THEN DISPLAY ws-negative. STOP RUN. END-IF. MOVE FUNCTION factorial(n) TO result. STRING 'The factorial of ' DELIMITED BY SIZE n DELIMITED BY SIZE ' is ' DELIMITED BY SIZE result DELIMITED BY SIZE INTO ws-output. DISPLAY ws-output. STOP RUN. FUNCTION-ID. factorial. LINKAGE SECTION. 01 num PIC 9(3). 01 factorial-result PIC 9(20). PROCEDURE DIVISION USING num RETURNING factorial-result. IF num = 0 THEN MOVE 1 TO factorial-result. ELSE COMPUTE factorial-result = num * FUNCTION factorial(num - 1). END-IF. EXIT FUNCTION. END FUNCTION factorial.
implicit none
integer, allocatable :: numbers(:)
integer :: i, n
real :: avg, median, stddev, sum, sum_dev
character(len=100) :: filename
integer :: ios
logical :: file_exists
! Prompt for filename
write(*,*) “Enter the filename:”
read(*,'(A)’) filename
! Try to open the file
open(unit=10, file=filename, status=’old’, action=’read’, iostat=ios)
if (ios /= 0) then
write(*,*) “Error opening file.”
stop
end if
! Count the number of integers in the file
n = 0
do
read(10, *, iostat=ios)
if (ios /= 0) exit
n = n + 1
end do
rewind(10)
! Allocate array for storing integers
allocate(numbers(n))
! Read integers into the array
do i = 1, n
read(10, *) numbers(i)
end do
close(10)
! Calculate average
sum = 0.0
do i = 1, n
sum = sum + numbers(i)
end do
avg = sum / n
! Calculate median
call quicksort(numbers, 1, n)
if (mod(n, 2) == 0) then
median = (numbers(n/2) + numbers(n/2 + 1)) / 2.0
else
median = numbers(n/2 + 1)
end if
! Calculate standard deviation
sum_dev = 0.0
do i = 1, n
sum_dev = sum_dev + (numbers(i) – avg) ** 2
end do
stddev = sqrt(sum_dev / n)
! Output the results
write(*, ‘(A, F10.2)’) “Average: “, avg
write(*, ‘(A, F10.2)’) “Median: “, median
write(*, ‘(A, F10.2)’) “Standard Deviation: “, stddev
! Deallocate the array
deallocate(numbers)
contains
subroutine quicksort(arr, low, high)
integer, intent(inout) :: arr(:)
integer, intent(in) :: low, high
integer :: pivot, i, j, temp
if (low < high) then
pivot = arr((low + high) / 2)
i = low
j = high
do while (i <= j)
do while (arr(i) < pivot)
i = i + 1
end do
do while (arr(j) > pivot)
j = j – 1
end do
if (i <= j) then
temp = arr(i)
arr(i) = arr(j)
arr(j) = temp
i = i + 1
j = j - 1
end if
end do
call quicksort(arr, low, j)
call quicksort(arr, i, high)
end if
end subroutine quicksort
end program statistics_calculator
PROGRAM-ID. StatisticsCalculator.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT InputFile ASSIGN TO ‘input.txt’
ORGANIZATION IS LINE SEQUENTIAL.
DATA DIVISION.
FILE SECTION.
FD InputFile.
01 InputRecord PIC 9(10).
WORKING-STORAGE SECTION.
01 NumbersTab.
05 Numbers OCCURS 1000 TIMES PIC 9(10).
01 N PIC 9(4) VALUE 0.
01 I PIC 9(4).
01 Avg PIC 9(5)V99 VALUE 0.
01 Median PIC 9(5)V99 VALUE 0.
01 Stddev PIC 9(5)V99 VALUE 0.
01 Sum PIC 9(5)V99 VALUE 0.
01 SumDev PIC 9(5)V99 VALUE 0.
01 FileStatus PIC 9(4).
01 Filename PIC X(100).
PROCEDURE DIVISION.
MAIN-PARAGRAH.
DISPLAY “Enter the filename:”.
ACCEPT Filename.
OPEN INPUT InputFile.
IF FileStatus NOT = 0
DISPLAY “Error opening file.”
STOP RUN
END-IF.
PERFORM VARYING I FROM 1 BY 1 UNTIL FileStatus NOT = 0
READ InputFile INTO InputRecord
AT END
MOVE 0 TO FileStatus
NOT AT END
MOVE InputRecord TO Numbers(I)
ADD 1 TO N
END-READ
END-PERFORM.
CLOSE InputFile.
PERFORM Calculate-Average.
PERFORM Sort-Numbers.
PERFORM Calculate-Median.
PERFORM Calculate-Stddev.
PERFORM Display-Results.
STOP RUN.
Calculate-Average.
MOVE 0 TO Sum.
PERFORM VARYING I FROM 1 BY 1 UNTIL I > N
ADD Numbers(I) TO Sum
END-PERFORM.
COMPUTE Avg = Sum / N.
Sort-Numbers.
PERFORM QuickSort(1, N).
QuickSort(LOW, HIGH).
IF LOW < HIGH THEN
MOVE Numbers((LOW + HIGH) / 2) TO Pivot
MOVE LOW TO I
MOVE HIGH TO J
PERFORM UNTIL I > J
PERFORM UNTIL Numbers(I) >= Pivot
ADD 1 TO I
END-PERFORM.
PERFORM UNTIL Numbers(J) <= Pivot
SUBTRACT 1 FROM J
END-PERFORM.
IF I <= J THEN
MOVE Numbers(I) TO Temp
MOVE Numbers(J) TO Numbers(I)
MOVE Temp TO Numbers(J)
ADD 1 TO I
SUBTRACT 1 FROM J
END-IF.
END-PERFORM.
PERFORM QuickSort(LOW, J)
PERFORM QuickSort(I, HIGH)
END-IF.
Calculate-Median.
IF MOD(N, 2) = 0 THEN
COMPUTE Median = (Numbers(N/2) + Numbers(N/2 + 1)) / 2
ELSE
MOVE Numbers(N/2 + 1) TO Median
END-IF.
Calculate-Stddev.
MOVE 0 TO SumDev.
PERFORM VARYING I FROM 1 BY 1 UNTIL I > N
COMPUTE SumDev = SumDev + (Numbers(I) – Avg) ** 2
END-PERFORM.
COMPUTE Stddev = SQRT(SumDev / N).
Display-Results.
DISPLAY “Average: ” Avg.
DISPLAY “Median: ” Median.
DISPLAY “Standard Deviation: ” Stddev.
END PROGRAM StatisticsCalculator.
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