COBOL To OCaml Converter
Other COBOL Converters
What Is COBOL To OCaml Converter?
A COBOL to OCaml converter is an online tool designed to translate COBOL code into OCaml efficiently. By leveraging technologies such as generative AI, machine learning, and natural language processing, this converter streamlines the process of transitioning between programming languages. The conversion process involves three key steps:
- Input: You submit the COBOL code that needs to be converted.
- Processing: The tool employs advanced algorithms to analyze the structure and syntax of the COBOL code. It identifies key elements such as variables, data types, and control flow constructs that are essential for accurate translation.
- Output: The output is the converted OCaml code, crafted to reflect the logic and functionality of the original COBOL code.
How Is COBOL Different From OCaml?
COBOL and OCaml represent two distinct eras and philosophies in programming languages, catering to different needs and preferences. COBOL, short for Common Business Oriented Language, is an older programming language primarily employed in business, finance, and administrative systems for organizations and government entities. Its design emphasizes clarity and readability, making it particularly suitable for large-scale data processing. The language’s syntax is characterized by its tendency to be verbose, often resembling plain English, which can make it easier for non-programmers to understand but may also result in more extensive code than necessary.
On the other hand, OCaml is a modern programming language that embraces functional programming, with additional support for imperative programming styles. Known for its robust type system, OCaml offers features such as type inference and pattern matching, allowing developers to write safer and more efficient code. Its concise and expressive syntax facilitates rapid development and reduces the chances of errors, making it particularly appealing for software developers and researchers in academia.
- COBOL:
- Follows a procedural programming style, focusing on step-by-step instructions.
- Strongly emphasizes data structures, making it effective for organized data manipulation.
- Its verbose syntax resembles plain English, aiding readability but sometimes leading to lengthy code.
- OCaml:
- Primarily utilizes functional programming concepts while allowing imperative capabilities.
- Features type inference, enabling the compiler to determine variable types automatically.
- Concise syntax promotes greater expressiveness and reduces boilerplate code.
| Feature | COBOL | OCaml |
|---|---|---|
| Paradigm | Procedural | Functional, Imperative |
| Syntax | Verbose, English-like | Concise, expressive |
| Type System | Static typing | Static typing with type inference |
| Use Case | Business, Finance | General-purpose, Academic, Software Development |
How Does Minary’s COBOL To OCaml Converter Work?
The Minary’s AI COBOL to OCaml converter operates through a streamlined process designed to transform your COBOL code into OCaml with ease. You start by filling in the ‘Describe the task in detail’ box on the left side of the interface. Here, you can outline the specifics of your COBOL code, whether it’s a complete program, specific functions, or even a segment that needs conversion. The more precise you are in this description, the better the output will be.
Once you’ve provided the necessary details, you simply click the ‘Generate’ button. The generator then processes your request, utilizing sophisticated algorithms to reinterpret the COBOL code into OCaml. Upon completion, the converted code appears in the adjacent section on the right. You’ll find a ‘Copy’ button at the bottom of this area that allows you to easily transfer the generated code to your clipboard for implementation or further editing.
For feedback, you’ll notice buttons that let you vote on whether the output met your expectations. This feedback loop is instrumental in continually training and refining the AI, enhancing its ability to deliver high-quality code transformations. Each vote helps improve the COBOL to OCaml converter for all users.
For a practical example, you might enter a prompt like: “Convert this COBOL data processing routine into OCaml.” After clicking generate, you could see the equivalent OCaml code formatted and ready for your use, simply waiting for you to click ‘Copy’ when you’re ready.
Examples Of Converted Code From COBOL To OCaml
PROGRAM-ID. SumAndAverage.
ENVIRONMENT DIVISION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 NUMBERS.
05 NUM-COUNT PIC 9(3) VALUE 0.
05 NUM-LIST OCCURS 100 TIMES
INDEXED BY IDX.
10 NUM PIC 9(5).
01 TOTAL PIC 9(7) VALUE 0.
01 AVERAGE PIC 9(5)V99 VALUE 0.
01 DISPLAY-MESSAGE PIC X(30).
PROCEDURE DIVISION.
MAIN-PARA.
DISPLAY “Enter how many numbers you want to sum (up to 100): “.
ACCEPT NUM-COUNT.
PERFORM VARYING IDX FROM 1 BY 1 UNTIL IDX > NUM-COUNT
DISPLAY “Enter number ” IDX “: “.
ACCEPT NUM(IDX).
END-PERFORM.
PERFORM VARYING IDX FROM 1 BY 1 UNTIL IDX > NUM-COUNT
ADD NUM(IDX) TO TOTAL
END-PERFORM.
IF NUM-COUNT > 0
COMPUTE AVERAGE = TOTAL / NUM-COUNT
ELSE
MOVE 0 TO AVERAGE
END-IF.
MOVE “Total: ” TO DISPLAY-MESSAGE.
STRING DISPLAY-MESSAGE DELIMITED BY SIZE
TOTAL DELIMITED BY SIZE INTO DISPLAY-MESSAGE
END-STRING.
DISPLAY DISPLAY-MESSAGE.
MOVE “Average: ” TO DISPLAY-MESSAGE.
STRING DISPLAY-MESSAGE DELIMITED BY SIZE
AVERAGE DELIMITED BY SIZE INTO DISPLAY-MESSAGE
END-STRING.
DISPLAY DISPLAY-MESSAGE.
STOP RUN.
let num_count = ref 0 in
let total = ref 0 in
let average = ref 0.0 in
let num_list = Array.make 100 0 in
Printf.printf “Enter how many numbers you want to sum (up to 100): “;
num_count := read_int ();
for idx = 1 to !num_count do
Printf.printf “Enter number %d: ” idx;
num_list.(idx – 1) <- read_int ()
done;
for idx = 1 to !num_count do
total := !total + num_list.(idx - 1)
done;
if !num_count > 0 then
average := float_of_int !total /. float_of_int !num_count
else
average := 0.0;
let display_message = Printf.sprintf “Total: %d” !total in
Printf.printf “%sn” display_message;
let display_message_avg = Printf.sprintf “Average: %.2f” !average in
Printf.printf “%sn” display_message_avg;
PROGRAM-ID. EmployeeReport.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT EmployeeFile ASSIGN TO ‘EMPLOYEE.DAT’
ORGANIZATION IS LINE SEQUENTIAL.
SELECT ReportFile ASSIGN TO ‘EMPLOYEE_REPORT.TXT’
ORGANIZATION IS LINE SEQUENTIAL.
DATA DIVISION.
FILE SECTION.
FD EmployeeFile.
01 EmployeeRecord.
05 EmployeeID PIC 9(5).
05 EmployeeName PIC X(30).
05 EmployeeSalary PIC 9(9)V99.
FD ReportFile.
01 ReportRecord PIC X(80).
WORKING-STORAGE SECTION.
01 TotalSalary PIC 9(9)V99 VALUE 0.
01 CountEmployees PIC 9(5) VALUE 0.
01 AverageSalary PIC 9(9)V99 VALUE 0.
01 AboveAverageCount PIC 9(5) VALUE 0.
01 Line PIC X(80).
PROCEDURE DIVISION.
MAIN-PROCEDURE.
OPEN INPUT EmployeeFile
OPEN OUTPUT ReportFile
PERFORM READ-EMPLOYEE-RECORDS
PERFORM CALCULATE-AVERAGE-SALARY
PERFORM WRITE-REPORT
CLOSE EmployeeFile
CLOSE ReportFile
STOP RUN.
READ-EMPLOYEE-RECORDS.
PERFORM UNTIL EOF
READ EmployeeFile INTO EmployeeRecord
AT END
SET EOF TO TRUE
NOT AT END
ADD EmployeeSalary TO TotalSalary
ADD 1 TO CountEmployees
END-READ
END-PERFORM.
CALCULATE-AVERAGE-SALARY.
IF CountEmployees > 0 THEN
COMPUTE AverageSalary = TotalSalary / CountEmployees
ELSE
MOVE 0 TO AverageSalary
END-IF.
WRITE-REPORT.
MOVE ‘Total Salary Expenditure: ‘ TO Line
STRING Line DELIMITED BY SIZE
TotalSalary DELIMITED BY SPACE INTO Line
WRITE ReportRecord FROM Line
MOVE ‘Employees earning above average salary:’ TO Line
WRITE ReportRecord FROM Line
REWIND EmployeeFile
PERFORM UNTIL EOF
READ EmployeeFile INTO EmployeeRecord
AT END
SET EOF TO TRUE
NOT AT END
IF EmployeeSalary > AverageSalary THEN
STRING EmployeeID DELIMITED BY SPACE
EmployeeName DELIMITED BY SPACE
EmployeeSalary DELIMITED BY SIZE INTO Line
WRITE ReportRecord FROM Line
END-IF
END-READ
END-PERFORM.
EOF BOOLEAN VALUE FALSE.
let open Printf in
let employee_file = “EMPLOYEE.DAT” in
let report_file = “EMPLOYEE_REPORT.TXT” in
let rec read_employee_records in_channel =
try
let line = input_line in_channel in
let parts = String.split_on_char ‘ ‘ line in
let employee_id = int_of_string (List.nth parts 0) in
let employee_name = String.concat ” ” (List.tl parts |> List.tl) in
let employee_salary = int_of_string (List.nth parts ((List.length parts) – 1)) in
(employee_id, employee_name, employee_salary) :: read_employee_records in_channel
with End_of_file -> []
in
let employees =
let in_channel = open_in employee_file in
let records = read_employee_records in_channel in
close_in in_channel;
records
in
let total_salary = List.fold_left (fun acc (_, _, salary) -> acc + salary) 0 employees in
let count_employees = List.length employees in
let average_salary = if count_employees > 0 then total_salary / count_employees else 0 in
let out_channel = open_out report_file in
fprintf out_channel “Total Salary Expenditure: %dn” total_salary;
fprintf out_channel “Employees earning above average salary:n”;
List.iter (fun (id, name, salary) ->
if salary > average_salary then
fprintf out_channel “%d %s %dn” id name salary
) employees;
close_out out_channel;
()
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