COBOL To Rust Converter
Other COBOL Converters
What Is COBOL To Rust Converter?
A COBOL to Rust converter is an online tool designed to facilitate the transition from COBOL code to Rust language. By using technologies such as generative AI, machine learning, and natural language processing, it streamlines the conversion of legacy code into modern syntax. This tool aims to address challenges that developers face when updating old systems, ensuring a smoother migration process.
The conversion takes place through a three-step process:
- Input: You provide the COBOL code that needs to be converted. The converter accepts the code in its existing format, ensuring that all relevant details are captured.
- Processing: The tool analyzes the provided code, interpreting its structure and logic. This involves breaking down the code into its components, understanding the relationships between variables, functions, and control flow. It utilizes algorithms that leverage machine learning to improve accuracy and efficiency.
- Output: The tool generates the equivalent Rust code, ready for further development. The output maintains the original program’s functionality while adopting Rust’s syntax and best practices.
How Is COBOL Different From Rust?
COBOL is a long-established programming language that finds its primary application in business, finance, and the operational frameworks of various organizations and government agencies. Its syntax prioritizes readability, which makes it accessible for handling structured data tasks. As a result, COBOL excels in environments where data processing is key. In contrast, Rust is a more contemporary language tailored for system-level programming. It aims to enhance safety and efficiency, particularly concerning concurrent processes, while also addressing common challenges associated with memory management.
Let’s explore the key differences that define these two languages:
| Feature | COBOL | Rust |
|---|---|---|
| Memory Management | Automatic with limited user control | Manual with a focus on an ownership model |
| Performance | High efficiency, particularly suited for batch processing tasks | High performance, providing low-level access for fine-tuning |
| Concurrency | Limited capabilities for handling multiple tasks simultaneously | Native support for safe concurrency, making it easier to write parallel code |
| Syntax | Verbose and resembles conversational English, making it easier for non-programmers to grasp | Concise and expressive, allowing developers to write complex tasks more efficiently |
| Community | A smaller community, primarily focused on maintaining legacy systems | A rapidly expanding community, particularly vibrant in systems programming |
Familiarizing yourself with these distinctions can significantly facilitate your transition from COBOL to Rust. This understanding not only helps you assess your programming needs but also assists in making informed choices about updating or modernizing legacy systems that may be critical to your operations.
How Does Minary’s COBOL To Rust Converter Work?
The Minary COBOL To Rust converter is designed for smooth and efficient code transformation, simplifying the task of migrating legacy COBOL code into modern Rust. Start by detailing the task you’d like the converter to execute in the provided text box on the left. This should include any specific aspects of the COBOL code you wish to convert or particular functionalities you want to retain in the Rust version.
Once you’ve input your description, simply click the “Generate” button. The system will process your request and translate your COBOL code into Rust, displaying the output on the right side of the screen. This result can be easily copied by using the “Copy” button located at the bottom of the output area, allowing you to seamlessly integrate the new code into your project.
The platform also includes feedback voting buttons below the generated code. These buttons let you share whether the output meets your expectations. Your feedback plays an important role in improving the model, enabling it to learn and refine its capabilities over time.
Here’s an example of a detailed prompt you might use: “Convert the COBOL payroll processing logic that calculates employee wages based on hours worked, including overtime rules, into Rust.” This kind of clear, specific instruction can yield a more accurate and useful Rust code output from the COBOL To Rust converter.
Examples Of Converted Code From COBOL To Rust
PROGRAM-ID. AverageCalculator.
ENVIRONMENT DIVISION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 Number PIC 9(3) VALUE 0.
01 Total PIC 9(6) VALUE 0.
01 Count PIC 9(3) VALUE 0.
01 Average PIC 9(5)V99 VALUE 0.
01 Continue PIC X VALUE ‘Y’.
PROCEDURE DIVISION.
MAIN-LOGIC.
DISPLAY “Enter a series of numbers (1 to stop):”
PERFORM UNTIL Continue = ‘N’
ACCEPT Number
IF Number = 1 THEN
MOVE ‘N’ TO Continue
ELSE
ADD Number TO Total
ADD 1 TO Count
END-IF
END-PERFORM.
IF Count > 0 THEN
COMPUTE Average = Total / Count
DISPLAY “Average is: ” Average
IF Average > 50 THEN
DISPLAY “The average is above 50.”
ELSE IF Average < 50 THEN
DISPLAY "The average is below 50."
ELSE
DISPLAY "The average is equal to 50."
END-IF
ELSE
DISPLAY "No numbers were entered."
END-IF.
STOP RUN.
use std::io;
let mut number: i32 = 0;
let mut total: i32 = 0;
let mut count: i32 = 0;
let mut continue_calculation = ‘Y’;
println!(“Enter a series of numbers (1 to stop):”);
while continue_calculation == ‘Y’ {
let mut input = String::new();
io::stdin().read_line(&mut input).expect(“Failed to read line”);
number = input.trim().parse().expect(“Please enter a valid number”);
if number == 1 {
continue_calculation = ‘N’;
} else {
total += number;
count += 1;
}
}
if count > 0 {
let average = total as f64 / count as f64;
println!(“Average is: {}”, average);
if average > 50.0 {
println!(“The average is above 50.”);
} else if average < 50.0 {
println!("The average is below 50.");
} else {
println!("The average is equal to 50.");
}
} else {
println!("No numbers were entered.");
}
}
PROGRAM-ID. EmployeeSalaryAnalysis.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT EmployeeFile ASSIGN TO ’employee_data.txt’
ORGANIZATION IS LINE SEQUENTIAL.
DATA DIVISION.
FILE SECTION.
FD EmployeeFile.
01 EmployeeRecord.
05 EmployeeID PIC 9(5).
05 EmployeeName PIC X(30).
05 EmployeeSalary PIC 9(7)V99.
WORKING-STORAGE SECTION.
01 WS-RecordCount PIC 9(5) VALUE 0.
01 WS-TotalSalary PIC 9(7)V99 VALUE 0.
01 WS-AverageSalary PIC 9(7)V99 VALUE 0.
01 WS-AboveAverageCount PIC 9(5) VALUE 0.
01 WS-AboveAverageDetails.
05 AboveAverageID PIC 9(5) OCCURS 100 TIMES.
05 AboveAverageName PIC X(30) OCCURS 100 TIMES.
05 AboveAverageSalary PIC 9(7)V99 OCCURS 100 TIMES.
01 WS-EndOfFile PIC X VALUE ‘N’.
PROCEDURE DIVISION.
MAIN-LOGIC.
OPEN INPUT EmployeeFile
PERFORM UNTIL WS-EndOfFile = ‘Y’
READ EmployeeFile INTO EmployeeRecord
AT END
MOVE ‘Y’ TO WS-EndOfFile
NOT AT END
ADD 1 TO WS-RecordCount
ADD EmployeeSalary TO WS-TotalSalary
IF EmployeeSalary > WS-AverageSalary
ADD 1 TO WS-AboveAverageCount
MOVE EmployeeID TO AboveAverageID(WS-AboveAverageCount)
MOVE EmployeeName TO AboveAverageName(WS-AboveAverageCount)
MOVE EmployeeSalary TO AboveAverageSalary(WS-AboveAverageCount)
END-IF
END-READ
END-PERFORM.
IF WS-RecordCount > 0
COMPUTE WS-AverageSalary = WS-TotalSalary / WS-RecordCount
END-IF.
DISPLAY ‘Average Salary: ‘ WS-AverageSalary
DISPLAY ‘Number of Employees above Average Salary: ‘ WS-AboveAverageCount.
IF WS-AboveAverageCount > 0
DISPLAY ‘Employees earning above the average salary:’
PERFORM VARYING WS-Index FROM 1 BY 1 UNTIL WS-Index > WS-AboveAverageCount
DISPLAY ‘ID: ‘ AboveAverageID(WS-Index)
DISPLAY ‘Name: ‘ AboveAverageName(WS-Index)
DISPLAY ‘Salary: ‘ AboveAverageSalary(WS-Index)
END-PERFORM
END-IF.
CLOSE EmployeeFile.
STOP RUN.
use std::io::{self, BufRead};
use std::path::Path;
const MAX_EMPLOYEES: usize = 100;
struct Employee {
id: u32,
name: String,
salary: f64,
}
fn main() -> io::Result<()> {
let path = Path::new(“employee_data.txt”);
let file = File::open(&path)?;
let reader = io::BufReader::new(file);
let mut employees: Vec
let mut total_salary = 0.0;
for line in reader.lines() {
let line = line?;
let id: u32 = line[0..5].trim().parse().unwrap();
let name = line[5..35].trim().to_string();
let salary: f64 = format!(“{}.{}”, &line[35..42].trim(), &line[42..44].trim()).parse().unwrap();
employees.push(Employee { id, name, salary });
total_salary += salary;
}
let record_count = employees.len() as u32;
let average_salary = if record_count > 0 { total_salary / record_count as f64 } else { 0.0 };
let above_average: Vec<&Employee> = employees.iter().filter(|&e| e.salary > average_salary).collect();
println!(“Average Salary: {:.2}”, average_salary);
println!(“Number of Employees above Average Salary: {}”, above_average.len());
if !above_average.is_empty() {
println!(“Employees earning above the average salary:”);
for emp in above_average {
println!(“ID: {}”, emp.id);
println!(“Name: {}”, emp.name);
println!(“Salary: {:.2}”, emp.salary);
}
}
Ok(())
}
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