COBOL To Haskell Converter
Other COBOL Converters
What Is COBOL To Haskell Converter?
A COBOL To Haskell converter is an online tool that utilizes generative AI, machine learning, natural language processing, and other advanced technologies to transform COBOL code into Haskell. This tool helps developers tackle the challenges of maintaining functionality while migrating legacy systems to modern programming languages.
The conversion process unfolds in three main steps:
- Input: You start by providing the COBOL code that needs conversion. This step ensures that the converter has the necessary information to begin the transformation.
- Processing: The tool analyzes the provided code and applies its algorithms to interpret the COBOL syntax and semantics. It maps the constructs from COBOL to their equivalent representations in Haskell, taking into account the unique features of both languages.
- Output: Once the analysis and translation are complete, you receive the converted Haskell code, which is ready for integration into your projects. This ensures a smoother transition and reduces the need for extensive modifications.
How Is COBOL Different From Haskell?
COBOL and Haskell represent two distinct approaches to programming, each serving unique purposes and environments. COBOL, which stands for Common Business-Oriented Language, is designed primarily for business applications that demand robust data processing. In contrast, Haskell is a purely functional language, which focuses on mathematical functions and immutability. If you are considering moving from COBOL to Haskell, appreciating these core differences will significantly aid your transition.
Here are some key distinctions:
- Paradigm: COBOL operates within an imperative and procedural framework, emphasizing step-by-step instructions. This allows for easy understanding of the flow of execution, crucial in business settings. Haskell, however, adopts a functional paradigm, illustrating how programs are constructed from pure functions instead of sequences, which can lead to clearer and more predictable code.
- Type System: COBOL employs a static type system with limited type inference, which means types must often be explicitly declared. Haskell’s type system is more advanced, providing strong type inference that can automatically deduce the types of expressions, enhancing code safety and reducing errors during development.
- Memory Management: In COBOL, developers manage memory explicitly, which provides control but demands careful attention to prevent errors like memory leaks. On the other hand, Haskell simplifies this with automatic garbage collection, allowing developers to focus on logic without worrying about manual memory handling.
- Variable Mutability: COBOL supports mutable state, meaning variables can be changed or updated throughout the program. Haskell promotes immutability, where once a variable is assigned a value, it cannot be altered. This approach leads to fewer side effects, making code easier to reason about.
| Feature | COBOL | Haskell |
|---|---|---|
| Paradigm | Procedural | Functional |
| Type System | Static, limited type inference | Advanced static, strong type inference |
| Memory Management | Explicit management | Garbage collection |
| Variable Mutability | Supports mutable variables | Promotes immutability |
How Does Minary’s COBOL To Haskell Converter Work?
Start by describing your task in detail in the provided field. This may include specific COBOL code or broader instructions about what needs conversion to Haskell. Each detail you provide will help fine-tune the output generated by the COBOL To Haskell converter. Once you’ve entered your details, simply click the ‘Generate’ button. The powerful engine behind the converter will then process your input and display the converted Haskell code on the right side of the screen.
You’ll notice a ‘Copy’ button at the bottom, which allows you to easily transfer the generated code for your use. Moreover, there are feedback vote buttons for you to indicate whether the code meets your expectations or not. This feedback is invaluable as it helps to improve the accuracy of the COBOL To Haskell converter over time.
As an example, if you enter a task such as “Convert this COBOL function that calculates factorials into Haskell,” the generator will analyze the instruction, generate the corresponding Haskell code, and display it promptly. You can then assess the output and provide feedback, contributing to the ongoing refinement of the tool.
Examples Of Converted Code From COBOL To Haskell
PROGRAM-ID. FactorialCalculator.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 User-Input PIC 9(3).
01 Result PIC 9(18) VALUE 1.
01 Counter PIC 9(3) VALUE 1.
01 Display-Result PIC X(50).
PROCEDURE DIVISION.
MAIN-PROCEDURE.
DISPLAY “Enter a non-negative integer: “.
ACCEPT User-Input.
IF User-Input < 0 THEN
DISPLAY "Error: Negative numbers do not have factorials."
ELSE
PERFORM CALCULATE-FACTORIAL.
MOVE "The factorial of " TO Display-Result.
STRING Display-Result DELIMITED BY SIZE
User-Input DELIMITED BY SIZE
" is " DELIMITED BY SIZE
Result DELIMITED BY SIZE
INTO Display-Result.
DISPLAY Display-Result.
END-IF.
STOP RUN.
CALCULATE-FACTORIAL.
PERFORM VARYING Counter FROM 1 BY 1 UNTIL Counter > User-Input
MULTIPLY Result BY Counter GIVING Result
END-PERFORM.
import Control.Monad (when)
main :: IO ()
main = do
putStrLn “Enter a non-negative integer: ”
userInput <- getLine
let userInputNum = read userInput :: Integer
when (userInputNum < 0) $
putStrLn "Error: Negative numbers do not have factorials."
let result = calculateFactorial userInputNum
let displayResult = "The factorial of " ++ show userInputNum ++ " is " ++ show result
putStrLn displayResult
calculateFactorial :: Integer -> Integer
calculateFactorial n = factorialHelper n 1
where
factorialHelper 0 acc = acc
factorialHelper m acc = factorialHelper (m – 1) (acc * m)
PROGRAM-ID. StudentGrades.
ENVIRONMENT DIVISION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 Student-Records.
05 Num-Students PIC 99.
05 Grades OCCURS 100 TIMES
INDEXED BY Grade-Index
PIC 99.
01 Total PIC 9999 VALUE 0.
01 Highest PIC 99 VALUE 0.
01 Lowest PIC 99 VALUE 100.
01 Average PIC 9999 VALUE 0.
01 Passing-Score PIC 99 VALUE 60.
01 I PIC 99 VALUE 1.
PROCEDURE DIVISION.
MAIN-LOGIC.
DISPLAY “Enter the number of students (1-100): ”
ACCEPT Num-Students.
PERFORM VARYING I FROM 1 BY 1 UNTIL I > Num-Students
DISPLAY “Enter grade for student ” I “: ”
ACCEPT Grades(I)
ADD Grades(I) TO Total
IF Grades(I) > Highest THEN
MOVE Grades(I) TO Highest
END-IF
IF Grades(I) < Lowest THEN
MOVE Grades(I) TO Lowest
END-IF
END-PERFORM.
IF Num-Students > 0 THEN
COMPUTE Average = Total / Num-Students
ELSE
MOVE 0 TO Average
END-IF.
DISPLAY “Total Grades: ” Total.
DISPLAY “Highest Grade: ” Highest.
DISPLAY “Lowest Grade: ” Lowest.
DISPLAY “Average Grade: ” Average.
IF Average >= Passing-Score
DISPLAY “The average is above or equal to passing.”
ELSE
DISPLAY “The average is below passing.”
END-IF.
STOP RUN.
import Control.Monad (forM_)
main :: IO ()
main = do
putStrLn “Enter the number of students (1-100): ”
numStudentsInput <- getLine
let numStudents = read numStudentsInput :: Int
let grades = replicate 100 0
let (total, highest, lowest) = collectGrades numStudents grades 0 0 100
let average = if numStudents > 0 then total `div` numStudents else 0
putStrLn $ “Total Grades: ” ++ show total
putStrLn $ “Highest Grade: ” ++ show highest
putStrLn $ “Lowest Grade: ” ++ show lowest
putStrLn $ “Average Grade: ” ++ show average
if average >= 60
then putStrLn “The average is above or equal to passing.”
else putStrLn “The average is below passing.”
collectGrades :: Int -> [Int] -> Int -> Int -> Int -> (Int, Int, Int)
collectGrades 0 grades total highest lowest = (total, highest, lowest)
collectGrades num students total highest lowest = do
let i = (100 – num) + 1
putStrLn $ “Enter grade for student ” ++ show i ++ “: ”
gradeInput <- getLine
let grade = read gradeInput :: Int
let newTotal = total + grade
let newHighest = max highest grade
let newLowest = min lowest grade
collectGrades (num - 1) students newTotal newHighest newLowest
SQL
Verilog
VHDL