COBOL To Fortran Converter
Other COBOL Converters
What Is COBOL To Fortran Converter?
An AI COBOL to Fortran converter is an advanced online tool specifically designed to transform COBOL code into Fortran. By employing technologies such as generative AI, machine learning, and natural language processing, this converter simplifies the migration of legacy systems into modern environments. The conversion process is clear and involves three main steps:
- Input: You start by providing the COBOL code that requires conversion, allowing the tool to understand what needs to be transformed.
- Processing: The converter analyzes the provided code. It utilizes sophisticated algorithms to interpret the syntax and logic of the COBOL code, ensuring that all elements are correctly understood before transformation.
- Output: Finally, the tool generates the corresponding Fortran code. This output is crafted to be equivalent in functionality, making it ready for immediate use in modern applications.
How Is COBOL Different From Fortran?
COBOL and Fortran serve distinct purposes within the programming landscape, catering to different needs and industries. COBOL, which stands for Common Business-Oriented Language, is largely utilized for business applications, focusing on data processing, reporting, and managing vast amounts of data. Its use in enterprise environments highlights its strengths in handling operations that require efficiency and accuracy, such as payroll systems, banking transactions, and inventory management systems. In contrast, Fortran, short for Formula Translation, is tailored for scientific computing and numerical calculations. It excels in high-performance computing tasks, making it the go-to choice for engineers and researchers who need to solve complex mathematical problems or run simulations.
Understanding these differences is crucial when transitioning from COBOL to Fortran. Each language offers its own set of advantages: COBOL’s syntax is designed to be readable, closely mirroring English, which helps developers maintain and modify code with greater ease. This readability is vital in business settings where programs need to be understood by various stakeholders, including non-technical personnel. Additionally, COBOL supports robust file handling and handles batch processing efficiently, making it well suited for large volumes of transaction-based data.
On the other hand, Fortran’s strengths lie in its ability to manage arrays and perform intricate mathematical operations. It is continuously updated to accommodate modern programming practices, ensuring it remains relevant in an ever-evolving field. Fortran’s syntax may be more complex, but it is optimized for speed and efficiency, qualities that are paramount in scientific research and engineering applications.
| Feature | COBOL | Fortran |
|---|---|---|
| Primary Focus | Business Processing | Scientific Computing |
| Syntax | English-like readability | Mathematical conventions |
| Performance | Batch Processing | High-performance calculations |
| Data Handling | Rich file handling | Complex arrays and functions |
How Does Minary’s COBOL To Fortran Converter Work?
The Minary COBOL To Fortran converter operates with a user-friendly interface designed to streamline the transition from COBOL to Fortran code. When you enter your task details in the provided field on the left, the system takes those specific instructions and comprehensively processes them to generate the corresponding Fortran code on the right-hand side.
Steps are straightforward: start by clearly describing the task at hand, ensuring you provide sufficient detail about what you need. This could include specifying the functionality or the parts of the COBOL code you want to convert. After you’ve filled in the details, click the ‘Generate’ button. Almost instantly, the generator will display the interpreted code on the right, ready for you to review. If you find the generated code satisfactory, you can easily copy it using the button at the bottom of the results area.
Moreover, there are feedback vote buttons available for you to indicate whether the output meets your expectations. Your feedback plays a vital role in refining the converter’s accuracy, allowing it to improve continuously with each submission.
For instance, if you input a prompt like “Convert the following COBOL procedure for calculating a factorial into Fortran,” the generator will analyze this request and produce precise Fortran code reflecting your initial prompt. Adjusting your input for clarity can also help enhance the output quality, ensuring a smoother conversion experience.
Examples Of Converted Code From COBOL To Fortran
PROGRAM-ID. FactorialCalculator.
ENVIRONMENT DIVISION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 User-Input PIC 9(3).
01 Factorial PIC 9(18) VALUE 1.
01 Counter PIC 9(3) VALUE 1.
01 Display-Message PIC X(50) VALUE “The factorial of the number is: “.
01 Result-Output PIC X(50).
PROCEDURE DIVISION.
MAIN-LOGIC.
DISPLAY “Enter a number (0 to 12): ”
ACCEPT User-Input
IF User-Input < 0 OR User-Input > 12
DISPLAY “Invalid Input! Please enter a number between 0 and 12.”
STOP RUN
END-IF
IF User-Input = 0
MOVE 1 TO Factorial
ELSE
PERFORM VARYING Counter FROM 1 BY 1 UNTIL Counter > User-Input
MULTIPLY Factorial BY Counter GIVING Factorial
END-PERFORM
END-IF
MOVE DISPLAY-MESSAGE TO Result-Output
STRING Result-Output DELIMITED BY SIZE
Factorial DELIMITED BY SIZE
INTO Result-Output
DISPLAY Result-Output
STOP RUN.
IMPLICIT NONE
INTEGER :: User_Input
INTEGER(KIND=8) :: Factorial = 1
INTEGER :: Counter
CHARACTER(LEN=50) :: Display_Message = “The factorial of the number is: ”
CHARACTER(LEN=50) :: Result_Output
PRINT*, “Enter a number (0 to 12): ”
READ*, User_Input
IF (User_Input < 0 .OR. User_Input > 12) THEN
PRINT*, “Invalid Input! Please enter a number between 0 and 12.”
STOP
END IF
IF (User_Input == 0) THEN
Factorial = 1
ELSE
DO Counter = 1, User_Input
Factorial = Factorial * Counter
END DO
END IF
WRITE(Result_Output, “(A, I24)”) Display_Message, Factorial
PRINT*, Trim(Result_Output)
END PROGRAM FactorialCalculator
PROGRAM-ID. EmployeeYearsOfService.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT InputFile ASSIGN TO ’employee_records.txt’
ORGANIZATION IS LINE SEQUENTIAL.
SELECT OutputFile ASSIGN TO ‘service_report.txt’
ORGANIZATION IS LINE SEQUENTIAL.
DATA DIVISION.
FILE SECTION.
FD InputFile.
01 InputRecord.
05 EmployeeID PIC 9(5).
05 EmployeeName PIC X(30).
05 StartYear PIC 9(4).
FD OutputFile.
01 OutputRecord PIC X(50).
WORKING-STORAGE SECTION.
01 WS-CurrentYear PIC 9(4) VALUE 2023.
01 WS-YearsOfService PIC 9(3).
01 WS-FormattedOutput PIC X(50).
01 WS-Header PIC X(50) VALUE ‘Employee ID | Name | Years of Service’.
01 WS-LineSpacing PIC X(1) VALUE ‘ ‘.
01 EOF-Indicator PIC X VALUE ‘N’.
PROCEDURE DIVISION.
MAIN-LOGIC.
OPEN INPUT InputFile
OPEN OUTPUT OutputFile
PERFORM WRITE-HEADER
PERFORM UNTIL EOF-Indicator = ‘Y’
READ InputFile INTO InputRecord
AT END
MOVE ‘Y’ TO EOF-Indicator
NOT AT END
PERFORM CALCULATE-YEARS-OF-SERVICE
PERFORM WRITE-OUTPUT
END-READ
END-PERFORM
CLOSE InputFile
CLOSE OutputFile
STOP RUN.
WRITE-HEADER.
MOVE WS-Header TO OutputRecord
WRITE OutputRecord.
CALCULATE-YEARS-OF-SERVICE.
COMPUTE WS-YearsOfService = WS-CurrentYear – StartYear.
WRITE-OUTPUT.
MOVE EmployeeID TO WS-FormattedOutput (1:5)
MOVE EmployeeName TO WS-FormattedOutput (7:36)
STRING WS-YearsOfService DELIMITED BY SIZE
INTO WS-FormattedOutput (38:50)
WRITE OutputRecord FROM WS-FormattedOutput.
IMPLICIT NONE
! Variable declarations
INTEGER :: EmployeeID
CHARACTER(LEN=30) :: EmployeeName
INTEGER :: StartYear
INTEGER :: WS_CurrentYear
INTEGER :: WS_YearsOfService
CHARACTER(LEN=50) :: WS_FormattedOutput
CHARACTER(LEN=50) :: WS_Header
CHARACTER(LEN=1) :: WS_LineSpacing
LOGICAL :: EOF_Indicator
CHARACTER(LEN=100) :: InputFileName, OutputFileName
INTEGER :: InputUnit, OutputUnit
! File names
InputFileName = ’employee_records.txt’
OutputFileName = ‘service_report.txt’
WS_CurrentYear = 2023
WS_Header = ‘Employee ID | Name | Years of Service’
EOF_Indicator = .FALSE.
! Open files
OPEN(UNIT=10, FILE=InputFileName, STATUS=’OLD’, ACTION=’READ’, IOSTAT=InputUnit)
OPEN(UNIT=11, FILE=OutputFileName, STATUS=’REPLACE’, ACTION=’WRITE’, IOSTAT=OutputUnit)
! Write header
WRITE(11,*) TRIM(WS_Header)
! Process records
DO WHILE (.NOT. EOF_Indicator)
READ(10, *, IOSTAT=InputUnit) EmployeeID, EmployeeName, StartYear
IF (InputUnit /= 0) THEN
EOF_Indicator = .TRUE.
ELSE
! Calculate years of service
WS_YearsOfService = WS_CurrentYear – StartYear
! Format output
WRITE(WS_FormattedOutput, ‘(I5, 1X, A30, 1X, I3)’) EmployeeID, EmployeeName, WS_YearsOfService
! Write output
WRITE(11,*) TRIM(WS_FormattedOutput)
END IF
END DO
! Close files
CLOSE(10)
CLOSE(11)
END PROGRAM EmployeeYearsOfService
SQL
Verilog
VHDL