C++ To COBOL Converter

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Convert hundreds of lines of C++ code into COBOL with one click. Completely free, no sign up required.

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What Is C++ To COBOL Converter?

An AI C++ To COBOL converter is an online tool that simplifies the process of converting C++ code into COBOL. It uses advanced technologies such as generative AI, machine learning, and natural language processing to assist developers and businesses in this often complex task.

The conversion process involves three clear steps:

Input: You begin by providing the C++ code you wish to convert. This could be a single function or an entire program, depending on your needs.
Processing: The tool then analyzes your code. Using its AI capabilities, it identifies the structure and semantics of the C++ code and maps them to the equivalent constructs in COBOL. This step ensures that the logic and functionality are preserved during the conversion.
Output: Finally, the tool generates the corresponding COBOL code, which you can immediately use in your projects.

How Is C++ Different From COBOL?

C++ and COBOL are two distinct programming languages, each crafted to serve unique purposes. C++ stands out as a robust, object-oriented language designed for developing system and application software. It is favored for its flexibility and performance in various contexts, especially in complex applications like video games or system software. On the other hand, COBOL’s primary focus is on business data processing, specifically in environments where large-scale transaction processing is essential. Understanding these fundamental differences is crucial when transitioning code between these two languages.

Here are some key distinctions to consider:

Programming Paradigm: C++ embraces multiple programming paradigms, allowing for procedural, object-oriented, and even functional programming styles. This versatility makes it suitable for a wide range of applications. In contrast, COBOL primarily follows a procedural paradigm, emphasizing straightforward step-by-step programming, which is intuitive for business logic.
Data Handling: In C++, data is organized using classes and a variety of data structures. This approach supports encapsulation and code modularity. COBOL, however, relies on a structure of records and fields, making it efficient for tabular data processing, common in financial applications.
Syntax: The syntax of C++ is often seen as more intricate, incorporating many symbols and operators that can enhance functionality but also introduce complexity. COBOL, in contrast, offers a more English-like syntax that prioritizes readability, although it can lead to verbose code which may not always be efficient.
Memory Management: C++ provides programmers with manual memory management options, granting them control over resource allocation and deallocation, which is crucial for performance in resource-intensive applications. COBOL abstracts away memory management details, allowing developers to focus on business logic without worrying about memory pointers.

For a more comprehensive look, here’s a summarized comparison:

Feature	C++	COBOL
Type System	Statically typed	Statically typed
Memory Management	Manual with pointers	Automatic, no pointers
Usage	System software, game development	Business applications, legacy systems
Community Support	Large developer community	Specialized business community

How Does Minary’s C++ To COBOL Converter Work?

The process begins by entering your task details into the input field. Describe the specific requirements of your C++ to COBOL translation, including any special considerations or parameters you want the converter to take into account. This could involve mentioning specific classes, functions, or data structures relevant to your project.

Once you’ve filled in the details, click the “Generate” button. The generator then processes your input, analyzing the provided information and converting the relevant C++ code snippets to COBOL format. This transformation takes into consideration the unique syntax and structure of both languages, ensuring a smooth translation. The generated code will appear on the right side of the interface.

After reviewing the output, you have the option to copy the generated code to your clipboard using the “Copy” button located at the bottom. This makes it easy for you to integrate the newly created COBOL code into your projects swiftly.

Feedback plays a vital role in improving the converter’s efficiency. If the generated code meets your expectations, utilize the feedback vote buttons to express your satisfaction. Positive feedback contributes to the ongoing training of the C++ to COBOL converter, helping it improve for future users.

For example, if you’re looking to convert a C++ class that handles a financial transaction system, you might enter: “Translate a C++ class that calculates interest rates based on principal, rate, and time into COBOL.” The generator will then process this request and provide you with the necessary COBOL code representation that you can utilize seamlessly.

Examples Of Converted Code From C++ To COBOL

#include
using namespace std;

// Function to calculate GCD using Euclidean algorithm
int gcd(int a, int b) {
while (b != 0) {
int temp = b;
b = a % b;
a = temp;
}
return a;
}

int main() {
int num1, num2;

// Prompting user for input
cout << "Enter two numbers: "; cin >> num1 >> num2;

// Calculating GCD
int result = gcd(num1, num2);

// Displaying the result
cout << "The greatest common divisor (GCD) of " << num1 << " and " << num2 << " is " << result << endl; return 0; }

IDENTIFICATION DIVISION.
PROGRAM-ID. GCDCalculator.

ENVIRONMENT DIVISION.

DATA DIVISION.
WORKING-STORAGE SECTION.
01 NUM1 PIC 9(5).
01 NUM2 PIC 9(5).
01 RESULT PIC 9(5).
01 TEMP PIC 9(5).

PROCEDURE DIVISION.

MAIN-PARAGRAPH.
DISPLAY “Enter two numbers: “.
ACCEPT NUM1.
ACCEPT NUM2.

PERFORM CALCULATE-GCD.

DISPLAY “The greatest common divisor (GCD) of ” NUM1 ” and ” NUM2 ” is ” RESULT.

STOP RUN.

CALCULATE-GCD.
IF NUM2 = 0 THEN
MOVE NUM1 TO RESULT
ELSE
PERFORM UNTIL NUM2 = 0
MOVE NUM2 TO TEMP
COMPUTE NUM2 = NUM1 MOD NUM2
MOVE TEMP TO NUM1
END-PERFORM
MOVE NUM1 TO RESULT
END-IF.

#include
#include
#include
#include

using namespace std;

class Room {
public:
string description;
vector items;
map exits;

Room(string desc) : description(desc) {}

void addItem(string item) {
items.push_back(item);
}

void addExit(string direction, Room* room) {
exits[direction] = room;
}

void showRoomStatus() {
cout << description << endl; if (!items.empty()) { cout << "You see: "; for (const string& item : items) { cout << item << " "; } cout << endl; } cout << "Exits: "; for (const auto& exit : exits) { cout << exit.first << " "; } cout << endl; } }; class Player { public: vector inventory;

void pickUpItem(string item) {
inventory.push_back(item);
cout << "You picked up: " << item << endl; } void showInventory() { if (inventory.empty()) { cout << "Your inventory is empty." << endl; } else { cout << "Inventory: "; for (const string& item : inventory) { cout << item << " "; } cout << endl; } } }; class Game { private: Player player; Room* currentRoom; public: Game() { Room* room1 = new Room("You are in a dimly lit room."); room1->addItem(“Key”);
Room* room2 = new Room(“You enter a bright room filled with treasures.”);
room2->addItem(“Gold Coin”);
Room* room3 = new Room(“You find yourself in a mysterious mage’s chamber.”);
room3->addItem(“Spell Book”);

room1->addExit(“north”, room2);
room2->addExit(“south”, room1);
room2->addExit(“east”, room3);
room3->addExit(“west”, room2);

currentRoom = room1;
}

void play() {
string command;
while (true) {
currentRoom->showRoomStatus();

cout << "What do you want to do? (move/pickup/view/inventory/exit) "; cin >> command;

if (command == “move”) {
string direction;
cout << "Enter direction: "; cin >> direction;

if (currentRoom->exits.count(direction)) {
currentRoom = currentRoom->exits[direction];
} else {
cout << "You can't go that way!" << endl; } } else if (command == "pickup") { if (!currentRoom->items.empty()) {
player.pickUpItem(currentRoom->items.back());
currentRoom->items.pop_back();
} else {
cout << "There are no items to pick up." << endl; } } else if (command == "view") { currentRoom->showRoomStatus();
} else if (command == “inventory”) {
player.showInventory();
} else if (command == “exit”) {
cout << "Thanks for playing!" << endl; break; } else { cout << "Invalid command!" << endl; } } } }; int main() { Game game; game.play(); return 0; }

IDENTIFICATION DIVISION.
PROGRAM-ID. TextAdventureGame.

ENVIRONMENT DIVISION.
DATA DIVISION.

WORKING-STORAGE SECTION.
01 WS-DIRECTION PIC X(20).
01 WS-COMMAND PIC X(20).
01 WS-ITEM PIC X(50).
01 WS-ITEMS OCCURS 0 TO 10 TIMES DEPENDING ON WS-ITEMS-COUNT.
05 WS-ITEM-ENTRY PIC X(50).
01 WS-ITEMS-COUNT PIC 9(2) VALUE 0.
01 WS-INVENTORY OCCURS 0 TO 10 TIMES DEPENDING ON WS-INVENTORY-COUNT.
05 WS-INVENTORY-ENTRY PIC X(50).
01 WS-INVENTORY-COUNT PIC 9(2) VALUE 0.
01 WS-ROOM-STATUS PIC X(100).
01 WS-EXIT-STATUS PIC X(100).
01 WS-ROOM1 PIC X(50) VALUE “You are in a dimly lit room.”.
01 WS-ROOM2 PIC X(50) VALUE “You enter a bright room filled with treasures.”.
01 WS-ROOM3 PIC X(50) VALUE “You find yourself in a mysterious mage’s chamber.”.
01 WS-CURRENT-ROOM PIC X(50) VALUE WS-ROOM1.
01 WS-EXITS OCCURS 0 TO 4 TIMES DEPENDING ON WS-EXITS-COUNT.
05 WS-EXIT-ENTRY PIC X(20).
01 WS-EXITS-COUNT PIC 9(2) VALUE 0.

PROCEDURE DIVISION.
MAIN-LOGIC.
PERFORM INITIALIZE-GAME
PERFORM GAME-LOOP
STOP RUN.

INITIALIZE-GAME.
MOVE “Key” TO WS-ITEMS(1).
ADD 1 TO WS-ITEMS-COUNT.
MOVE “Gold Coin” TO WS-ITEMS(2).
ADD 1 TO WS-ITEMS-COUNT.
MOVE “Spell Book” TO WS-ITEMS(3).
ADD 1 TO WS-ITEMS-COUNT.

MOVE “north” TO WS-EXIT-ENTRY(1).
ADD 1 TO WS-EXITS-COUNT.
MOVE “south” TO WS-EXIT-ENTRY(2).
ADD 1 TO WS-EXITS-COUNT.
MOVE “east” TO WS-EXIT-ENTRY(3).
ADD 1 TO WS-EXITS-COUNT.
MOVE “west” TO WS-EXIT-ENTRY(4).
ADD 1 TO WS-EXITS-COUNT.

GAME-LOOP.
PERFORM SHOW-ROOM-STATUS
DISPLAY “What do you want to do? (move/pickup/view/inventory/exit) “.
ACCEPT WS-COMMAND.

EVALUATE WS-COMMAND
WHEN “move”
DISPLAY “Enter direction: “.
ACCEPT WS-DIRECTION.
PERFORM MOVE-ROOM
WHEN “pickup”
PERFORM PICKUP-ITEM
WHEN “view”
PERFORM SHOW-ROOM-STATUS
WHEN “inventory”
PERFORM SHOW-INVENTORY
WHEN “exit”
DISPLAY “Thanks for playing!”.
EXIT PROGRAM
WHEN OTHER
DISPLAY “Invalid command!”.
END-EVALUATE.

PERFORM GAME-LOOP.

SHOW-ROOM-STATUS.
DISPLAY WS-CURRENT-ROOM.
IF WS-ITEMS-COUNT > 0
DISPLAY “You see: ” WITH NO ADVANCING
PERFORM VARYING WS-I FROM 1 BY 1 UNTIL WS-I > WS-ITEMS-COUNT
DISPLAY WS-ITEMS(WS-I) WITH NO ADVANCING
END-PERFORM
DISPLAY SPACE.
END-IF.
DISPLAY “Exits: ” WITH NO ADVANCING
PERFORM VARYING WS-I FROM 1 BY 1 UNTIL WS-I > WS-EXITS-COUNT
DISPLAY WS-EXIT-ENTRY(WS-I) WITH NO ADVANCING
END-PERFORM
DISPLAY SPACE.

MOVE-ROOM.
EVALUATE WS-DIRECTION
WHEN “north”
MOVE WS-ROOM2 TO WS-CURRENT-ROOM
WHEN “south”
MOVE WS-ROOM1 TO WS-CURRENT-ROOM
WHEN “east”
MOVE WS-ROOM3 TO WS-CURRENT-ROOM
WHEN “west”
MOVE WS-ROOM2 TO WS-CURRENT-ROOM
WHEN OTHER
DISPLAY “You can’t go that way!”.
END-EVALUATE.

PICKUP-ITEM.
IF WS-ITEMS-COUNT > 0
MOVE WS-ITEMS(WS-ITEMS-COUNT) TO WS-ITEM.
ADD 1 TO WS-INVENTORY-COUNT.
MOVE WS-ITEM TO WS-INVENTORY-ENTRY(WS-INVENTORY-COUNT).
DISPLAY “You picked up: ” WS-ITEM.
SUBTRACT 1 FROM WS-ITEMS-COUNT
ELSE
DISPLAY “There are no items to pick up.”.
END-IF.

SHOW-INVENTORY.
IF WS-INVENTORY-COUNT = 0
DISPLAY “Your inventory is empty.”.
ELSE
DISPLAY “Inventory: ” WITH NO ADVANCING
PERFORM VARYING WS-I FROM 1 BY 1 UNTIL WS-I > WS-INVENTORY-COUNT
DISPLAY WS-INVENTORY(WS-I) WITH NO ADVANCING
END-PERFORM.
DISPLAY SPACE.
END-IF.